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Integrate four algebraic shapes of Rubi's family 1 left by the earlier passes - #1997
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…r passes - A linear beside a power of a block P^q, q >= 2: the root -d/e named while the series and the rest are computed, the rest summed over one denominator in powers of the block's base and split into Q_q/P^q + ... + Q_1/P, each integrated with named coefficients. Carried as -d/e, the coefficients reached 14,000 characters and the answer 203,000. - A sum of powers of x times a symbolic power of a linear in a root of x: the answer G L T(u) with u = x^(1/k), T's coefficients solved from the highest power down, the equation left over deciding elementarity. - Under t = sqrt(L1)/sqrt(L2), powers of a - c t^q and of t stripped and the compound coefficients named, where the denominator has a complete quadratic factor with a symbol in it. - A polynomial over the cube root of a quadratic beside another with the same axis, shifted to y = x + b/(2c) and written in depressed form. Rubi's 1.3.1:568 and 569, 1.2.3.2:621, 1.2.1.4:1097 and 1.2.1.6:232 are answered and checked by quadrature; 1.3.1:562 and 567 and the two-radical rows 1098-1100 get shorter and faster; 125 neighbours keep their verdicts and every unchanged answer is identical. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Five of family 1's last six unsolved rows, by four mechanisms:
P^q,q >= 2(1.3.1:568 and 569), insideIntegrateOverAPowerOfALinearBesideABlock. The root-d/eis named while the series and the rest are computed. The rest is summed over one denominator in powers of the block's base, split intoQ_q/P^q + … + Q_1/P, and each piece is integrated with named coefficients. Carried as-d/e, the coefficients reached about 14,000 characters, the lowest-terms step gave up on the expanded(a + c ρ^4)^6, and 568's answer came to 203,000 characters.G L T(u)withu = x^(1/k). T's coefficients are solved from the highest power down, and the one equation left over decides whether the sum is elementary. The answer is differentiated back before it is returned.t = sqrt(L1)/sqrt(L2)(1.2.1.4:1097), insideSolveByAQuotientOfTwoLinearRadicals. Powers ofa - c t^qand oftare stripped and the compound coefficients named. This runs only where the denominator has a complete quadratic factor with a symbol in it, sincea + c x^2rows got longer when named.y = x + b/(2c)and written in depressed form, which turns it into a row master already answers.Measured on
8270086f, branch against master:Re-run alone, against master:
1.2.1.5:155 is the sixth row; #1992 answered it.
The other two moves, 3.2.1:292 and 7.4.1:369, are answered on both builds at a 60 s budget, with the same allocation to 0.001%. Every answer was checked at four or five pin sets on both signs, and by quadrature. 232 reads wrong under the probe's principal cube root at
c < 0. With the library's real odd roots, its derivative matches the integrand to 100 digits; the test asserts it atc = -0.8.Rebased on #1992, which changed the same family's answers: AX's six rows and #1992's rows (1.2.1.5:18, 19, 148, 154 and 155) all answer on the combined build, and both PRs' 367 tests pass. Of AX's 125 neighbours, no verdict is lost, and every unchanged answer is the same character for character. None of the problems answered on both builds allocates more on the branch.
Four new test classes differentiate the answers back.
BREAKING-CHANGES.mdhas four entries, with the 2.5.0 column measured on v2.5.0.Part of #233.
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https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura