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Integrate six seams of the independent suites - #1996
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Rafael-SOWNet merged 1 commit intoOct 21, 2026
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- A logarithmic part past the twelfth degree, up to the sixteenth, where every residue lies in a field of degree at most two (Hearn 365), with a mod-p screen that leaves before factoring a resultant whose factor of degree three or more shows modulo a prime. - e^(x + e^x) kept whole as a substitution's candidate (Hebisch 15). - The root of a real square beside a constant off the real line over a power of a real linear, its sign kept on the real line (Welz 44). - A rational function times sqrt(c x^2 + d sqrt(P))/sqrt(P), P = a + b x^4, c^2 = b d^2, as two roots of quadratics (Welz 47, 48). - A symbolic power inside a reciprocal of a root (Timofeev 448). - A rational function of x and ln(x) over distinct linears in ln(x), split into partial fractions in ln(x) (Bronstein 22). Rubi's 3.5:364 is answered too. The moves re-run alone go from 3 to 9 answered; 3.2.1:292 and 3.5:37, answered on both builds in 21-34 s, time out under load and allocate the same on both at a 60 s budget. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Seven problems of the Bronstein, Hearn, Hebisch, Timofeev and Welz suites were declined or ran out of time. Six small changes answer them:
P^2 - 2 Q^2, and its residues are the roots of4 t^2 - 4 t - 1, giving two logarithms ofP ± sqrt(2) Q. A mod-p screen leaves the path before factoring wherever a factor of the resultant of degree three or more shows modulo a prime.e^(x + e^x)kept whole as a substitution's candidate. Hebisch's(1 + e^x) e^(x + e^x)/(x + e^x)isEi(x + e^x).sqrt(c x^2 + d sqrt(P))/sqrt(P), withP = a + b x^4andc^2 = b d^2. It is written as two roots of quadratics (Welz 47 and 48).1/((1 + x^(2n)) sqrt((1 + x^(2n))^(1/n) - x^2))isarctan(x/sqrt((1 + x^(2n))^(1/n) - x^2)).L = ln(x)over distinct linears inL, split into partial fractions inL. Bronstein's(2 L^2 - L - x^2)/(L^3 - x^2 L)becomes the logarithmic integral and two logarithms. This applies only for two linears or more, and only where nothing answers the integrand whole; it is dispatched at the very end.Measured on
8a1ef454, branch against master:Re-run alone, nine moves are answered against three on master. Bronstein 22, Hearn 365, Hebisch 15, Timofeev 448, Welz 44, 47 and 48, and Rubi's 3.5:364 go from unevaluated to answered. Family 0 goes from 1,789 to 1,796.
Two problems master answers in 21–34 s, 3.2.1:292 and 3.5:37, timed out on the branch when re-run alone. At a 60 s budget both builds answer them, with the same allocation to 0.001% (34.2 and 37.0 GB), so the branch does not reach them. The one-row difference in the sample is 6.4.2:50, which both builds answer alone, in 18 and 21 s. No run had a wrong answer.
The rebase met two rules master had appended at the end of the dispatch; this one goes after them.
SeamsOfTheIndependentSuitesIntegralTestdifferentiates the answers back, and the 533 related tests pass.BREAKING-CHANGES.mdhas the entry, with the 2.5.0 column measured on v2.5.0.Part of #233.
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https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura